Function DeclaredSubset(subsetName, supersetName)


The function DeclaredSubset returns 1 if both subsetName and superName refer to a one-dimensional set and subsetName is directly or indirectly declared to be a subset of supersetName.

     subsetName,        ! (input) scalar element parameter
     supersetName       ! (input) scalar element parameter



An element expression in the predefined set AllIdentifiers.


An element expression in the predefined set AllIdentifiers.

Return Value

This function returns 1 iff subsetName is directly or indirectly a subset of supersetName. If subsetName or supersetName does not refer to a one-dimensional set, this function will return 0 without any warning or error message.


With the following declarations:

Set MasterSet {
    Index        :  ms;
Set DomainSet {
    SubsetOf     :  MasterSet;
    Index        :  ds;
Set ActiveSet {
    SubsetOf     :  DomainSet;
    Index        :  as;
File outf {
    Name         :  "outf.put";

The following statements:

put outf ;
put "ActiveSet(=DomainSet =", DeclaredSubset('ActiveSet', 'DomainSet'):0:0,/;
put "ActiveSet(=MasterSet =", DeclaredSubset('ActiveSet', 'MasterSet'):0:0,/;
put "MasterSet(=ActiveSet =", DeclaredSubset('MasterSet', 'ActiveSet'):0:0,/;
put "MasterSet(=outf      =", DeclaredSubset('MasterSet', 'outf'     ):0:0,/;
putclose ;

Return the following output.

ActiveSet(=DomainSet =1 ! ActiveSet is directly a subset of DomainSet
ActiveSet(=MasterSet =1 ! ActiveSet is indirectly a subset of MasterSet
MasterSet(=ActiveSet =0 ! But the reverse is not true.
MasterSet(=outf      =0 ! outf isn't even a set.

See also

The function IndexRange.