- Function DeclaredSubset(subsetName, supersetName)
DeclaredSubset
The function DeclaredSubset
returns 1 if both subsetName and
superName refer to a one-dimensional set and subsetName
is directly
or indirectly declared to be a subset of supersetName
.
DeclaredSubset(
subsetName, ! (input) scalar element parameter
supersetName ! (input) scalar element parameter
)
Arguments
- subsetName
An element expression in the predefined set
AllIdentifiers
.- supersetName
An element expression in the predefined set
AllIdentifiers
.
Return Value
This function returns 1 iff
subsetName
is directly or indirectly a subset ofsupersetName
. IfsubsetName
orsupersetName
does not refer to a one-dimensional set, this function will return 0 without any warning or error message.
Example
With the following declarations:
Set MasterSet {
Index : ms;
}
Set DomainSet {
SubsetOf : MasterSet;
Index : ds;
}
Set ActiveSet {
SubsetOf : DomainSet;
Index : as;
}
File outf {
Name : "outf.put";
}
The following statements:
put outf ;
put "ActiveSet(=DomainSet =", DeclaredSubset('ActiveSet', 'DomainSet'):0:0,/;
put "ActiveSet(=MasterSet =", DeclaredSubset('ActiveSet', 'MasterSet'):0:0,/;
put "MasterSet(=ActiveSet =", DeclaredSubset('MasterSet', 'ActiveSet'):0:0,/;
put "MasterSet(=outf =", DeclaredSubset('MasterSet', 'outf' ):0:0,/;
putclose ;
Return the following output.
ActiveSet(=DomainSet =1 ! ActiveSet is directly a subset of DomainSet
ActiveSet(=MasterSet =1 ! ActiveSet is indirectly a subset of MasterSet
MasterSet(=ActiveSet =0 ! But the reverse is not true.
MasterSet(=outf =0 ! outf isn't even a set.
See also
The function
IndexRange
.